1,32-9y^2=-3,09

Solution for 1,32-9y^2=-3,09 equation:

1.32-9y^2=-3.09

We move all terms to the left:

1.32-9y^2-(-3.09)=0

We add all the numbers together, and all the variables

-9y^2+4.41=0

a = -9; b = 0; c = +4.41;
Δ = b2-4ac
Δ = 02-4·(-9)·4.41
Δ = 158.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{158.76}}{2*-9}=\frac{0-\sqrt{158.76}}{-18}
=-\frac{\sqrt{}}{-18}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{158.76}}{2*-9}=\frac{0+\sqrt{158.76}}{-18}
=\frac{\sqrt{}}{-18}
$